1826 Virginia gubernatorial election
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A gubernatorial election was held in Virginia on December 9, 1826.[1] The incumbent governor of Virginia John Tyler was re-elected unanimously.[5]
The election was conducted by the Virginia General Assembly in joint session.[3] Tyler's first term was generally considered successful, and he faced no opposition to his bid for re-election.[6] He was elected unanimously on the first ballot.[5]
General election
[edit]| Candidate | First ballot | |
|---|---|---|
| Count | Percent | |
| John Tyler | ** | 100.00 |
Total
|
**
|
100.00
|
Notes
[edit]- ^ The Journal of the House of Delegates does not list parties for this election.[1] Chitwood states that Tyler as governor "did not have behind him in the legislature a dominant and well-disciplined party;"[2] Sobel and Raimo say that Tyler served in the U.S. House of Representatives as a Democratic-Republican;[3] while Kallenbach and Kallenbach list Tyler as a Jeffersonian Republican during his tenure.[4]
- ^ a b Virginia 1826, p. 22.
- ^ Chitwood 1964, p. 64.
- ^ a b Sobel & Raimo 1978, p. 1634.
- ^ Kallenbach & Kallenbach 1977, p. 613.
- ^ a b "John Tyler, Esq. [...]". Martinsburg Gazette and Public Advertiser. December 21, 1826.
- ^ Chitwood 1964, pp. 70–71.
- ^ "Election of Governor". Enquirer. December 13, 1825.
Bibliography
[edit]- Chitwood, Oliver Perry (1964). John Tyler: Champion of the Old South. New York: Russell and Russell.
- Kallenbach, Joseph E.; Kallenbach, Jessamine S. (1977). American State Governors, 1776–1976. Vol. 1. Dobbs Ferry, NY: Oceana Publications.
- Sobel, Robert; Raimo, John (1978). Biographical Directory of the Governors of the United States 1789–1978. Vol. 4. Westport, CT: Meckler Books.
- Virginia (1826). Journal of the House of Delegates [...]. Richmond.
